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Created: Tuesday, 10 December 2013 Written by Ehab Eldeeb
Solutions are purely written by Ehab Eldeeb
Enjoy :)
Unlike the strings sheet, this sheet is really poor .. only five questions here..
If you have any more ideas and want them solved, send me the question on facebook.
Download the sheet from this link --> Download here
First loop should be for rows, and the second for columns (as a standard)
And it's preferred to initialize the array inside the main function, not before it.
for (int i = 0; i < ROW-SIZE; i++)
for (int j = 0; j < COLUMN-SIZE; j++)
z[i][j] = x[i][j] + y[i][j];
int main(){
int x[4][4], y[4][4];// Read the two arrays
for (int i = 0; i < 4; i++){
for (int j = 0; j < 4; j++){
printf("Enter Element [%d][%d] for the array X: ", i+1, j+1);
scanf("%d", &x[i][j]);
printf("Enter Element [%d][%d] for the array Y: ", i+1, j+1);
scanf("%d", &y[i][j]);
}
}
return 0;
}
Adding or Subtracting Matrices is as easy as how it's shown in Question 2
Transpose means invert rows into columns and columns into rows
You will need to create a transposed array first, then transfer the values to it
Example: to transpose int x[5][4]; .. you will need to make int y[4][5];
for (int i = 0; i < 4; i++){
for (int j = 0; j < 5; j++){
y[j][i] = x[i][j];
}
}
The diagonal means i = j
(0,0), (1,1), (2,2), (3,3), ...etc.
int sum = 0;
for (int i = 0; i < 5; i++){
for (int j = 0; j < 5; j++){
if (i == j)
sum += x[i][j];
}
}
First Part:
for (int i = 0; i < 5; i++){
for (int j = 0; j < 5; j++){
if (x[i][j] != 0)
num++;
}
}
Second Part:
int prod = 1;
for (int i = 0; i < 5; i++){
for (int j = 0; j < 5; j++){
if (i == j)
prod *= x[i][j];
}
}
That's all about that sheet.
(Question "4" or "5 Second Part") .. If you want to get sum or product of:
elements above the diagonal ... change the if condition to: j > i
elements under the diagonal ... change the if condition to: i > j
Matrix problems should be for educational purpose, not for examination.